FRQ 1 - 2019
FRQ 1 on 2019
This frq from 2019 deals with a calendar where you have to write two methods of the class in order to calculate the number of leap years between year1 and year2 inclusively as well as write a method that returns an integer representing the day of the week for the given date (month, day, year).
Part A
Write the static method numberOfLeapYears, which returns the number of leap years between year1 and year2, inclusive. In order to calculate this value, a helper method is provided for you. • isLeapYear(year) returns true if year is a leap year and false otherwise. Complete method numberOfLeapYears below. You must use isLeapYear appropriately to receive full credit.
// Part A solution
public static int numberOfLeapYears(int year1, int year2){
int numLeapYears = 0;
for(int i = year1; i <= year2, i++){
if(isLeapYear(i)){
numLeapYears++;
}
}
return numLeapYears;
}
Part B
Write the static method dayOfWeek, which returns the integer value representing the day of the week for the given date (month, day, year), where 0 denotes Sunday, 1 denotes Monday, ..., and 6 denotes Saturday. For example, 2019 began on a Tuesday, and January 5 is the fifth day of 2019. As a result, January 5, 2019, fell on a Saturday, and the method call dayOfWeek(1, 5, 2019) returns 6. As another example, January 10 is the tenth day of 2019. As a result, January 10, 2019, fell on a Thursday, and the method call dayOfWeek(1, 10, 2019) returns 4. In order to calculate this value, two helper methods are provided for you. • firstDayOfYear(year) returns the integer value representing the day of the week for the first day of year, where 0 denotes Sunday, 1 denotes Monday, ..., and 6 denotes Saturday. For example, since 2019 began on a Tuesday, firstDayOfYear(2019) returns 2. • dayOfYear(month, day, year) returns n, where month, day, and year specify the nth day of the year. For the first day of the year, January 1 (month = 1, day = 1), the value 1 is returned. This method accounts for whether year is a leap year. For example, dayOfYear(3, 1, 2017) returns 60, since 2017 is not a leap year, while dayOfYear(3, 1, 2016) returns 61, since 2016 is a leap year. Complete method dayOfWeek below. You must use firstDayOfYear and dayOfYear appropriately to receive full credit.
// Part B Solution
public static int daysOfWeek(int month, int day, int year){
int firstDay = firstDayOfYear(year);
int nth = dayOfYear(month, day, year);
int returnDay = ((firstDay + nth) -1) % 7;
return returnDay;
}
public class APCalendar{
/** Returns true if year is a leap year and false otherwise. */
private static boolean isLeapYear(int year)
{ /* implementation not shown */ }
/** Returns the number of leap years between year1 and year2, inclusive.
* Precondition: 0 <= year1 <= year2
*/
public static int numberOfLeapYears(int year1, int year2){
int numLeapYears = 0;
for(int i = year1; i <= year2, i++){
if(isLeapYear(i)){
numLeapYears++;
}
}
return numLeapYears;
}
/** Returns the value representing the day of the week for the first day of year,
* where 0 denotes Sunday, 1 denotes Monday, ..., and 6 denotes Saturday.
*/
private static int firstDayOfYear(int year)
{ /* implementation not shown */ }
/** Returns n, where month, day, and year specify the nth day of the year.
* Returns 1 for January 1 (month = 1, day = 1) of any year.
* Precondition: The date represented by month, day, year is a valid date.
*/
private static int dayOfYear(int month, int day, int year)
{ /* implementation not shown */ }
/** Returns the value representing the day of the week for the given date
* (month, day, year), where 0 denotes Sunday, 1 denotes Monday, ...,
* and 6 denotes Saturday.
* Precondition: The date represented by month, day, year is a valid date.
*/
public static int daysOfWeek(int month, int day, int year){
int firstDay = firstDayOfYear(year);
int nth = dayOfYear(month, day, year);
int returnDay = ((firstDay + nth) -1) % 7;
return returnDay;
}
// There may be instance variables, constructors, and other methods not shown.
}